Answer:
1. 26.30 g C.
2. 4.42 g H.
3. 35.04 g O.
Explanation:
Hello there!
In this case, according to the given information, it turns out possible for us to calculate the required as follows:
1. Here, the only source of carbon is in CO2, and thus, we calculate the grams of carbon from the produced grams of this substance:
[tex]m_C=96.38gCO_2*\frac{1molCO_2}{44.01gCO_2} *\frac{1molC}{1molO_2} *\frac{12.01gC}{1molC} =26.30g[/tex]
2. Here, the only source of hydrogen is in H2O, and thus, we calculate the grams of hydrogen from the produced grams of this substance:
[tex]m_H=39.46gH_2O*\frac{1molH_2O}{18.02gH_2O} *\frac{2molH}{1molH_2O} *\frac{1.01gH}{1molH} =4.42gH[/tex]
3. Here, we subtract the mass of H and C from the mass of the sample, to obtain the mass of oxygen:
[tex]m_O=65.76g-26.30g-4.42g\\\\m_O=35.04g[/tex]
Regards!