Let ƒ(x) = 5x2 – x + 1 and g(x) = –3x. Evaluate the composition (ƒ ∘ g)(1) .
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Answer:
D
Step-by-step explanation:
We are given the two functions:
[tex]f(x) = 5x^2-x+1 \text{ and } g(x) = -3x[/tex]
And we want to find:
[tex](f \circ g)(1)[/tex]
Recall that this is equivalent to:
[tex]=f(g(1))[/tex]
Evaluate g(1):
[tex]g(1) = -3(1) = -3[/tex]
Substitute:
[tex]=f(-3)[/tex]
Evaluate f(-3):
[tex]f(-3)=5(-3)^2-(-3)+1=49[/tex]
Therefore:
[tex](f \circ g)(1) =49[/tex]
Our answer is D.
Answer:
49
Step-by-step explanation:
ƒ(x) = 5x2 – x + 1 and g(x) = –3x
(ƒ ∘ g)(1)
First find g(1) = -3(1) = -3
Then find f(g(1) = f(-3)
f(-3) = 5(-3)^2 - (-3) +1 = 5(9) +3+1 = 45+4 = 49