Answer:
Step 1:
N
H
+
3
C
H
2
C
H
2
N
H
+
3
(
a
q
)
⇌
A.
K
a
1
B.
K
a
2
C.
K
b
1
D.
K
b
2
Step 2:
N
H
2
C
H
2
C
H
2
N
H
+
3
(
a
q
)
⇌
A.
K
a
1
B.
K
a
2
C.
K
b
1
D.
K
b
2
Acid-
Ethylenediammonium ion refers to an organic compound with the chemical formula C₂H₄(NH⁺₃)₃. From its ammonia complex, its characteristics include:
The dissociation of a chemical compound(here, it's Ethylenediammonium) is the disintegration of a compound into simpler compounds or elements that may typically be recombined mostly under distinct conditions.
The dissociation of ethylenediammonium ion occurs in two stages and can be represented as follows:
From above, the formation of hydrogen ion H⁺ indicates that ethylenediammonium ion is an acid.
Thus, in the first dissociation, the equilibrium constant can be represented as: [tex]\mathbf{Ka_1}[/tex]
[tex]\mathbf{NH_3^+ CH_2CH_2NH_3^+_{(aq)} \rightleftharpoons^{\mathbf{Ka_1}} NH_2CH_2CH_2NH_3^+_{(aq)}+H^+_{(aq)}}[/tex]
The second stage of the dissociation can now be expressed as:
[tex]\mathbf{NH_2 CH_2CH_2NH_3^+_{(aq)} \rightleftharpoons ^{\mathbf{Ka_2}} NH_2CH_2CH_2NH_2_{(aq)}+H^+_{(aq)}}[/tex]
From above, we will notice that the equilibrium constant is [tex]\mathbf{Ka_2}[/tex]
Thus, from the above explanation, we can see the complete two acid dissociation reactions for ethylenediammonium ion and the correct symbol for the equilibrium constant for each reaction.
Learn more about acid dissociation reactions here:
https://brainly.com/question/15825860?referrer=searchResults
