Respuesta :

Eduard22sly

Answer:

8 cm

Explanation:

From the question given above, the following data were obtained:

Initial velocity (u) = 20 cm/s

Height (h) = 80 cm

Horizontal distance (s) =?

Next, we shall determine the time taken for marble to get to the ground. This can be obtained as follow:

Height (h) = 80 cm

Acceleration due to gravity (g) = 1000 cm/s²

Time (t) =?

t = √(2h/g)

t = √[(2 × 80)/1000]

t = √(160/1000)

T = √0.16

t = 0.4 s

Finally, we shall determine the horizontal distance travelled by the marble. This can be obtained as illustrated below:

Initial velocity (u) = 20 cm/s

Time (t) = 0.4 s

Horizontal distance (s) =?

s = ut

s = 20 × 0.4

s = 8 cm

Thus, the horizontal distance travelled by the marble is 8 cm.

onyebuchinnaji

The horizontal distance traveled by the marble is 8 cm.

The given parameters;

  • speed of the marble, v = 20 cm/s
  • height of the table, h = 80 cm

The time of motion of the marble is calculated as follows;

[tex]h = ut + \frac{1}{2} gt^2\\\\h = 0 + \frac{1}{2} gt^2\\\\h = \frac{1}{2} gt^2\\\\gt^2 = 2h\\\\t^2 = \frac{2h}{g} \\\\t = \sqrt{\frac{2h}{g} } \\\\t = \sqrt{\frac{2\times 0.8}{9.8} }\\\\t = 0.4 \ s[/tex]

The horizontal distance traveled by the marble is calculated as follows;

[tex]X = v_0_x t\\\\X = (20 \times 0.4)\\\\X = 8 \ cm[/tex]

Thus, the horizontal distance traveled by the marble is 8 cm.

Learn more here:https://brainly.com/question/2411455

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