Respuesta :
- Principal=P=2000
- Rate of interest=12%
- Time=2years and 6months=2.5years
- Interest=I
[tex]\boxed{\sf I=\dfrac{PRT}{100}}[/tex]
[tex]\\ \sf\longmapsto I=\dfrac{2000(12)(2.5)}{100}[/tex]
[tex]\\ \sf\longmapsto I=\dfrac{24000(2.5)}{100}[/tex]
[tex]\\ \sf\longmapsto I=\dfrac{60000}{100}[/tex]
[tex]\\ \sf\longmapsto I=600[/tex]
Given
- Principal (P) = 2000
- Rate of interest (R) = 12%
- Time (T) = 2 years 6 months
To Find
- Simple Interest
Formula Using
[tex] \large\begin{gathered} {\underline{\boxed{ \rm {\red{S.I \: = \: \frac{P × R × T}{100} }}}}}\end{gathered} [/tex]
Basic Terms
- Simple Interest - Simple interest is the method of calculating interest charged on the amount invested in a fixed deposit.
- Principle - The principal is the amount due on any debt before interest, or the amount invested before returns.
- Rate - An interest rate is the percentage of principal charged by the lender for the use of its money.
- Time = Time is duration (in months or years) in Simple Interest.
Solution
As we know that , first we need to convert 2 years 6 months into years.
[tex] \sf \ \implies \: 1 \: \: year \: = \: 12 \: \: months[/tex]
[tex] \sf \implies \: 2 \: \: years \: \: and \: \: 6 \: \: months \: = \: 30 \: \:months[/tex]
[tex] \sf \implies \: \:\frac{ \cancel{30} \: \: ^{2.5 \: \: years} }{ \cancel{12 \: }} \\ [/tex]
[tex]\bf{\blue{ Time \: = \: 2.5 \: \: years}}[/tex]
- Now , we have to find the Simple interest.
[tex]\Large\rm{\orange{ \begin{cases} \large\begin{gathered} {\underline{\boxed{ \rm {\purple{S.I \: = \: \frac{P × R × T}{100} }}}}}\end{gathered} \end{cases}}}[/tex]
Substuting the values
[tex] \tt \large \longrightarrow \: \: S.I \: = \: \frac{2000 \: × \: 12 × \: 2.5}{100} \\ [/tex]
[tex] \tt \large \longrightarrow \: \: S.I \: = \frac{60000}{100} \\ [/tex]
[tex]\tt \large \longrightarrow \: \: S.I \: = \frac{600 \cancel0 \cancel0}{1 \cancel0 \cancel0} \\ [/tex]
[tex]\tt \large \longrightarrow \: \: S.I \: = \: 600[/tex]
[tex]\large \underbrace{\textrm {{{\color{navy}{Simple Interest \: = \: 600}}}}}[/tex]