Respuesta :
Answer:
Step-by-step explanation:
369 = x + (x+2) + (x+4)
369 = 3x + 6
363 = 3x
121 = x
now that we know that x = 121, we can solve the equation by plugging in the variable
369 = x + (x+2) + (x+4)
369 = 121 + 123 + 125
369 = 369
The smallest three integers are 121,123 and 125.
Let, the smallest odd integers be n
Then according to the given condition,
[tex]n+(n+2)+(n+4)=369\\3n+6=369\\3n=363\\n=121[/tex]
So, the numbers are,
[tex]n=121\\n+2=121+2=123\\n+4=121+4=125[/tex]
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