Segment overline BD bisects angle ABC . Solve for Round to the nearest tenth, if necessary (Image not necessarily to scale.)
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Answer:
Hello,
Answer 52/3
Step-by-step explanation:
using the theorem of the bissector :
[tex]\dfrac{x}{13} =\dfrac{20}{15 } \\\\x=\dfrac{20*13}{15} \\\\x=\dfrac{52}{3}[/tex]
The value of x to the nearest tenth is 18.5
To get the value of x, we first need to get the height of the triangle.
[tex]h^2=20^2-15^2\\h^2=400-225\\h^2=175\\h=13.23[/tex]
Next is to get the value of x
[tex]x^2=13^2+13.2^2\\x^2=343.24\\x=18.52[/tex]
Hence the value of x to the nearest tenth is 18.5
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