The standard form equation of the line connecting the two points is [tex]2x + y = -2[/tex]
Linear equation in a standard form is given as [tex]Ax + By = C[/tex]
where,
A, B, and C are constants or numbers
x and y are the variables.
To solve this problem, the following steps would be taken:
Step 1: Find the slope of the line connecting points (-3,4) and (2,-6)
[tex]slope (m) = \frac{y_2 - y_1}{x_2 - x_1}[/tex]
where,
[tex](x_1, y_1) = (-3,4)\\(x_2, y_2) = (2,-6)[/tex]
Substitute
[tex]slope (m) = \frac{-6 - 4}{2 -(-3)} \\m = \frac{-10}{5}\\m = -2[/tex]
Step 2: Find the y-intercept (b) of the line by substituting [tex](x, y) = (-3,4)[/tex] and [tex]m = -2[/tex] into [tex]y = mx + b[/tex] (slope-intercept form)
[tex]4 = -2(-3) + b\\4 = 6 + b\\4 - 6 = 6 + b - 6\\-2 = b\\b = -2[/tex]
Step 3: Write the equation of the line in slope-intercept form by substituting [tex]m = -2[/tex] and [tex]b = -2[/tex] into [tex]y = mx + b[/tex]
[tex]y = -2x + (-2)\\y = -2x - 2[/tex]
Step 4: Rewrite the equation in standard form [tex](Ax + By = C)[/tex]
[tex]y = -2x - 2\\[/tex]
Add [tex]2x[/tex] to both sides
[tex]2x + y = -2x - 2 + 2x\\2x + y = -2[/tex]
The standard form equation of the points (-3,4) and (2,-6) is [tex]2x + y = -2[/tex]
Learn more about standard form of two points of a linear equation here:
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