Respuesta :
Its a binomial
[tex]\\ \sf\longmapsto x^2-6x+5=0[/tex]
- a=1
- b=-6
- c=5
If zeros be alpha and beta
[tex]\\ \sf\longmapsto \alpha+\beta=\dfrac{-b}{a}[/tex]
[tex]\\ \sf\longmapsto \alpha+\beta=\dfrac{-(-6)}{1}[/tex]
[tex]\\ \sf\longmapsto \alpha+\beta=6[/tex]
the sum of the factors of the trinomial [tex]x^2-6x+5[/tex] is -6
Given :
A trinomial [tex]x^2-6x+5[/tex]
The given trinomial is in the form of [tex]ax^2+bx+c[/tex]
Compare the given trinomial with standard form and write the value of a,b,c
a=1, b=-6 and c=5
Sum of the factors of the trinomial is [tex]\frac{b}{a} =-\frac{-6}{1} =-6[/tex]
So, the sum of the factors of the trinomial is -6
Learn more : brainly.com/question/19800260