here we want to multiply different monomials, the particular important thing about this problem is learning how to simplify these multiplications.
Here we need to remember the property:
[tex]a^n*a^m = a^{n + m}[/tex]
Now we want to directly multiply the monomials:
a) a³ , -6 a² b and 2 b³
Here we just have:
[tex]a^3*(-6*a^2*b)*(2*b^3)[/tex]
Let's reorder that, so we can separate the variables and the coefficients, so then we can use the above property to solve this:
[tex]a^3*(-6*a^2*b)*(2*b^3) = (-6*2)*(a^3*a^2)*(b*b^3) = -12*a^5*b^4[/tex]
b) 16 x⁶ , -10 xy² and 3/5 x² y²
Like before, we want to simplify:
[tex](16*x^6)*(-10*x*y^2)*(\frac{3}{5}*x^2*y^2)[/tex]
Again, reordering that we get:
[tex](16*\frac{3}{5}*-10)*(x^6*x*x^2)*(y^2*y^2)[/tex]
Now solving each parenthesis:
[tex](16*\frac{3}{5}*-10)*(x^6*x*x^2)*(y^2*y^2) = -96*x^{6 +1 + 2}*y^{2 + 2}[/tex]
Simplifying the last expression we get:
[tex]-96*x^{6 +1 + 2}*y^{2 + 2} = -96*x^9*y^4[/tex]
c) -4 p² q² and 3/8 pq²
Here we want to simplify:
[tex](-4*p^2*q^2)*(\frac{3}{8}*p*q^2)[/tex]
Using the same approach as before, we will get:
[tex](-4*p^2*q^2)*(\frac{3}{8}*p*q^2) = (-4*\frac{3}{8})*(p^2*p)*(q^2*q^2) = \frac{-3}{2}*p^3*q^4[/tex]
If you want to learn more, you can read:
https://brainly.com/question/17825040
