The surface area of the rectangular pyramid is the sum of the area of its individual surface. The surface area of the pyramid is 384 square inches.
Each surface of the rectangular pyramid has the shape of a triangle.
So that the area of each surface of the pyramid = [tex]\frac{1}{2}[/tex] x base x height.
From the given question;
The area of one of the two lateral faces = [tex]\frac{1}{2}[/tex] x b x h
= [tex]\frac{1}{2}[/tex] x 10 x 15
The area of one of the two lateral faces = 75 square inches
Thus,
the area of the first two given lateral faces = 2 x 75
= 150 square inches
The area of the first two given lateral faces = 150 square inches
Also,
The area of one of the other two lateral faces = [tex]\frac{1}{2}[/tex] x b x h
= [tex]\frac{1}{2}[/tex] x 18 x 13
The area of one of the other two lateral faces = 117 square inches
So that;
the area of the first two other lateral faces = 2 x 117
= 234 square inches
The area of the first two other lateral faces = 234 square inches
Thus,
the surface area of the pyramid = 150 + 234
= 384 square inches
Therefore, the surface area of the rectangular pyramid is 384 square inches.
For more clarifications: https://brainly.com/question/23564399
