Hi there!
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I believe your answer is:
[tex]\boxed{m= \frac{y-5}{x-6}}; \text{ } x\neq 6[/tex]
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Here’s why:
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[tex]\boxed{\text{Solving for 'm'...}}\\\\y-5=m(x-6)\\------------\\\rightarrow m(x-6) = y-5\\\\\rightarrow \frac{m(x-6)=y-5}{(x-6)}; x\neq 6\\\\\rightarrow \boxed{m= \frac{y-5}{x-6}}; \text{ } x\neq 6[/tex]
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Hope this helps you. I apologize if it’s incorrect.
