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A car is coasting with a velocity of 25 m/s to the right. The driver suddenly applied the brakes and begins to decelerate the car at a rate of -2 m/s2. If we neglect the reaction time of the driver, how far (in meters) does the car travel before coming to a complete stop?

Respuesta :

onyebuchinnaji

The distance traveled by the car before coming to a complete stop is 156.25 m

The given parameter:

initial velocity of the car, u = 25 m/s

acceleration of the car, a = - 2 m/s²

The distance traveled by the car before coming to a complete stop is calculated as;

[tex]v^2 = u^2 + 2as\\\\2as = v^2 - u^2\\\\s = \frac{v^2-u^2}{2a} \\\\when \ the \ car \ stops \ the \ final \ velocity \ v = 0\\\\s = \frac{-u^2}{2a} \\\\s = \frac{- (25)^2}{2(-2)} = 156.25 \ m[/tex]

Thus, the distance traveled by the car before coming to a complete stop is 156.25 m

Learn more here: https://brainly.com/question/17129121

okpalawalter8

We have that the car's travel before coming to a complete stop is

S=156.3m

From the question we are told that

A car is coasting with a velocity of 25 m/s

decelerate the car at a rate of -2 m/s2.

Generally the Newtons equation for the  distance is mathematically given as

[tex]S=\frac{v^2}{2a}[/tex]

Therefore

S=\frac{25^2}{2*2}

S=156.3m

Therefore

the car's travel before coming to a complete stop is

S=156.3m

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https://brainly.com/question/22271063?referrer=searchResults

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