Respuesta :
ANswer:-
Yes, it would occur without additional energy because the reaction is exothermic.
Explanation :-
Find Hydrogen enthalpies of both sides
Reactant=413+839+432=1684KJ/mol
Product=413KJ/mol
Clearly shown
[tex]\\ \bull\sf\dashrightarrow \Delta H=-ve[/tex]
Hence its an exothermic reaction.
Yes, the reaction would occur without additional energy because the reaction is exothermic.
We have to calculate the reaction enthalpy using the values of bond energy provided as follows;
ΔH(reaction) = ∑bond energies of bonds being broken - ∑bond energies of the bonds being formed.
Hence;
ΔH(reaction) =∑[839 + 3 (432)) + 2(413)] kJ/mol - ∑2(4×413) kJ/mol
ΔH(reaction) = (839 + 1296 + 826) kJ/mol - 3304 kJ/mol
ΔH(reaction) = 2961 kJ/mol - 3304 kJ/mol = -343 kJ/mol
Yes, the reaction would occur without additional energy because the reaction is exothermic.
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