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27. CHALLENGE The car in Figure 16 travels west with a forward acceleration of 0.22 m/s2. What was the car's velocity (v) at point x if it travels a distance of 350 m in 18.4 s?
Vi = ? x x Figure 16

Respuesta :

abidemiokin

The car's velocity (v) at point x, if it travels a distance of 350 m in 18.4 s is 12.41m/s

According to the equation of motions;

v² = u² + 2as

Given that

v is the final velocity

u is the initial velocity

a is the acceleration

s is the distance

Given the following parameters

u = 0m/s

a = 0.22m/s²

s = 350m

Susbstitute the given values into the formula

v² = 0² + 2(0.22)(350)

v² = 154

v = √154

v = 12.41 m/s

Hence the car's velocity (v) at point x, if it travels a distance of 350 m in 18.4 s is 12.41m/s

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