Respuesta :

Answer:

From general equation of a line:

[tex]y = mx + b[/tex]

m » slope, b » y-intercept.

but perpendicularly:

[tex]m _{1} \times m _{2} = - 1 \\ - 3 \times m = - 1 \\ m = \frac{1}{3} [/tex]

at point (6, 2):

[tex]2 = ( \frac{1}{3} \times 6) + b \\ 2 = 2 + b \\ b = 0[/tex]

therefore, equation is :

[tex]{ \boxed{ \boxed{y = \frac{1}{3} x}}}[/tex]

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