Q 1 . How many significant figures are in the following measurement? 0.0009(1 point)


1


5

4


3

Q 2. Three unique samples are weighed on different scales at separate laboratories across the country. The first has a weight of 31.2 lbs, the second sample weighs 38.02 lbs, while the third measures 45 lbs. How much is the total combined weight of all of these samples?(1 point)


114.22 lbs

110 lbs

114 lbs

114.2 lbs

Q 3. A track coach measures the 100-meter time of a track athlete. The runner completes the distance in 11.5 seconds. If the stopwatch has an uncertainty of 1.7%, what is the amount of uncertainty in the time?(1 point)
(1 point)

11.5 s ± 0.19 s
11.5 s plus or minus 0.19 s

11.5 s ± 0.20 s
11.5 s plus or minus 0.20 s

11.5 s ± 0.1955 s
11.5 s plus or minus 0.1955 s

11.5 s ± 0.196 s


Q 4. The speed of a bullet train is measured to be 312.0 mph ± 3.9 mph. What is the percent uncertainty in this measurement?(1 point)


1.3%

1.2%

1.25%

0.0125%

Respuesta :

Here we have some questions about experimental errors.

Q1) We want to see how many significant figures have the measure:

0.0009

The number of significant figures is the number of known digits that are not the leading zeros.

Here we can see four leading zeros, and a single-digit different than zero, which is a 9.

Then we have only one significant figure, the 9.

Q2) Here we will use the measure that is the less exact, as the error of that measure may be larger than the smaller significant figures of the other measures.

Then:

31.2 lb + 38.02lb + 45 lb

The worst measure is 45lb, so the smallest significant figure that we should use is the first one at the left of the decimal point, then we need to round the other two measures to the next whole number, we will get:

31 lb + 38 lb + 45 lb = 114lbs

Q3) We know that the measure is 11.5 seconds and the uncertainty of 1.7%, then the uncertainty will be the 1.7% of the above measure:

(1.7%/100%)*11.5 s = 0.1955 s

Notice that our measure has one significant figure after the decimal point, so we need to round the error to the same significant figure.

0.1955 s ≈ 0.2s

Then the measure is:

11.5 s ± 0.20 s

Q4) We have the measure:

312.0 mph ± 3.9 mph.

The percent uncertainty will be the quotient between the error and the measure times 100%, or:

(3.9 mph/312.0 mph)*100%  = 1.25%

This is a percent error, we do not need to round this.

If you want to learn more, you can read:

https://brainly.com/question/17339020

Answer:

Q1) Answer: 1

Q2) Answer: 114 lbs

Q3) Answer: 11.5 s ± 0.2 s

Q4) Answer: 1.3%

Just took the test and these were correct