Using improper fractions, the solution for the expression is:
[tex]-\frac{49}{12}[/tex]
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The expression is given by:
[tex]-2\frac{1}{3} + (-1\frac{3}{4}) = -2\frac{1}{3} - 1\frac{3}{4}[/tex]
Converting the improper fractions to standard:
[tex]-2\frac{1}{3} = -2 - \frac{1}{3} = -\frac{6}{3} - \frac{1}{3} = -\frac{7}{3}[/tex]
[tex]-1\frac{3}{4} = -1 - \frac{3}{4} = -\frac{4}{4} - \frac{3}{4} = -\frac{7}{4}[/tex]
Solving the expression:
[tex]-2\frac{1}{3} - 1\frac{3}{4} = -\frac{7}{3} - \frac{7}{4} = -\frac{28 + 21}{12} = -\frac{49}{12}[/tex]
A similar problem is given at https://brainly.com/question/16725183
