The mass that the aerogel insulation added to the aircraft, with respect to glass, is 8.8 × 10³ g.
The density of the aerogel is 0.00011 lb/in³. We will convert it to g/cm³ using the following conversion factors:
[tex]\frac{0.00011lb}{in^{3} } \times \frac{454g}{1lb} \times \frac{1in^{3} }{16.4cm^{3} } = 0.0030 g/cm^{3}[/tex]
If the maximum space for insulation in the spacecraft's hull was 2921 cm³, the mass that would occupy the aerogel with a density of 0.0030 g/cm³ is:
[tex]2921 cm^{3} \times \frac{0.0030g}{cm^{3} } = 8.8 g[/tex]
Glass is about 1000 times denser than aerogel. That is,
[tex]0.0030 g/cm^{3} \times 1000 = 3.0 g/cm^{3}[/tex]
If the maximum space for insulation in the spacecraft's hull was 2921 cm³, the mass that would occupy the glass with a density of 3.0 g/cm³ is:
[tex]2921 cm^{3} \times \frac{3.0g}{cm^{3} } = 8.8 \times 10^{3} g[/tex]
The mass that would add the aerogel with respect to the glass is:
[tex]8.8 \times 10^{3} g - 8.8 g \approx 8.8 \times 10^{3} g[/tex]
The mass that the aerogel insulation added to the aircraft, with respect to glass, is 8.8 × 10³ g.
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