Let A= (3.0 m, 20 0 south of east), B = (2.0 m, north), and C= (5.0 m, 70 0 south of
west).
a. Draw and label A , B, and C with their tails at the origin. Use a coordinate system
with the x-axis to the east.
b. b. Write A, B, and C in component form, using unit vectors.
c. c. Find the magnitude and the direction of D = A + B+ C.

Respuesta :

A point (x, y) can be written in polar form as (R, θ), such that:

x = R*cos(θ)

y = R*sin(θ)

Where R is the magnitude and θ is the angle measured from the positive x-axis that defines the direction.

The correct answers are:

a) You can see the image at the end.

b) A = (2.82m, -1.03m)

   B = (0m, 2.0m)

   C = (-4.7m,  -1.7m)

c) D = (2.02m, 21.22°).

a) Let's define east as the positive x-axis, north as the positive y-axis.

Here we have:

A = (3.0m, 20° sout of east) = (3.0m, -20°)

B = (2.0m, north) = (2.0m, 90°)

C = (5.0m, 70° sout of west) = (5.0m, 250°)

The graph of the 3 vectors can be seen in the image below.

b) We want to write A, B, and C in component form.

We start with A  =  (3.0m, -20°)

x = 3.0m*cos(-20°) = 2.82m

y = 3.0m*sin(-20°) = -1.03m

A = (2.82m, -1.03m)

B = (2.0m, 90°)

x = 2.0m*cos(90°) = 0m

y = 2.0m*sin(90°) = 2.0m

B = (0m, 2.0m)

C = (5.0m, 250°)

x = 5.0m*cos(250°) = -1.7m

y = 5.0m*sin(250°) = -4.7m

C = (-4.7m,  -1.7m)

c) Now we want to find the magnitude and direction of:

D = A + B + C

  = (2.82m, -1.03m) + (0m, 2.0m) +  (-4.7m,  -1.7m)

  = (2.82m + 0m - 4.7m, -1.03m + 2.0m - 1.7m)

  = (-1.88m, -0.73m)

The magnitude is given by:

[tex]R = \sqrt{(-1.88)^2 + (-0.73)^2} = 2.02m[/tex]

To find the direction, or the angle, we can write:

θ = Atan(y/x) = Atan(-0.73m/-1.88m) = 21.22°

Then we can write D as:

D = (2.02m, 21.22°).

If you want to learn more, you can read:

https://brainly.com/question/12053471

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