Over which interval is the function f(x)=x^3-27/x^2-9 differentiable?
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Answer:
Step-by-step explanation:
F(x)=x³-27/x²-9
F(x)=(-9)³-27/(-9)²-9
F(x)=-729-27/-81-9
F(x)=-756/-90
F(x)=42/5