what is the current in the 30 ohm heating coil of a coffee maker that operates on a 120 volt circuit?

I attached an image with the other questions too ​

what is the current in the 30 ohm heating coil of a coffee maker that operates on a 120 volt circuitI attached an image with the other questions too class=

Respuesta :

Answer:

4Amps. i can't see other questions clearly

Explanation:

[tex]using ohms law \\ v = ir[/tex]

  • V=120 volt
  • R=30ohms
  • I=?

I=V/R

I=120/30

I=4amps

4) The current passing through heating coil of the coffee maker is 0.4A.

5) The resistance that allows the battery to produve the given amount of current is 1000Ω.

6) The resistance of the curling iron that draws the given amount of current in the circuit is 10Ω.

Ohm's law

Ohm's law states that "the voltage across the cross-section of a conductor is directly proportional to the current passing through it.

It is expressed as;

V = I × R

Where V is voltage, I is current and R is resistance.

For question 4)

  • Resistance R = 30Ω
  • Voltage V = 120V
  • Current I = ?

So, from the expression above,

V = I × R

I = V / R

I = 12V / 30Ω

I = 0.4A

Therefore, the current passing through heating coil of the coffee maker is 0.4A.

For question 5)

  • Voltage V = 6V
  • Current I = 0.006A
  • Resistance R = ?

So, from the expression above,

V = I × R

R = V / I

R = 6V / 0.006A

R = 1000Ω

Therefore, the resistance that allows the battery to produve the given amount of current is 1000Ω.

For question 6)

  • Voltage V = 120V
  • Current I = 12.0A
  • Resistance R = ?

So, from the expression above,

V = I × R

R = V / I

R = 120V / 12.0A

R = 10Ω

Therefore, the resistance of the curling iron that draws the given amount of current in the circuit is 10Ω.

Learn more about Ohm's law here: brainly.com/question/15088213