Respuesta :

  • Initial velocity=u=10m/s
  • Acceleration=a=4m/s^2
  • Time=t=8s

Final velocity be v

[tex]\\ \bull\tt\longmapsto v=u+at[/tex]

[tex]\\ \bull\tt\longmapsto v=10+4(8)[/tex]

[tex]\\ \bull\tt\longmapsto v=10+32[/tex]

[tex]\\ \bull\tt\longmapsto v=42m/s[/tex]

Answer:

• From the first newtons equation of motion:

[tex]{ \boxed{ \bf{v = u + at}}}[/tex]

v » final velocity which is required.

u » initial velocity, u = 10 m/s

a » acceleration, a = 4 m/s²

t » time, t = 8 seconds

Substitute:

[tex]v = 10 + (4 \times 8) \\ v = 10 + 32 \\ v = 42 \: m {s}^{ - 1} \\ \\ { \underline{ \underline{ \bf{ \: \: final \: velocity = 42 \: m {s}^{ - 1} }}}}[/tex]