The linear equation y=mx+b containing the point (-5, 5) and perpendicular to the line 5x+25y=11 is y = -5/11 x + 30/11
The formula for finding the equation of a line in point-slope form is expressed as:
y-y0 = m(x-x0) where:
m is the slope
(x0, y0) is any point on the line
Given the following
(x0, y0) = (-5, 5)
Get the slope of the given line 5x+25y=11.
Rewrite in the form y = mx+b
25y = -5x + 11
y = -5/11 x + 11/25
Compare with the original equation
mx = -5/11 x
m = -5/11
Get the required equation
y - 5 = -5/11(x-(-5))
11(y-5) = -5(x+5)
11y-55 = -5x - 25
11y+5x = -25 + 55
11y+5x = 30
11y = -5x + 30
y = -5/11 x + 30/11
Hence the linear equation y=mx+b containing the point (-5, 5) and perpendicular to the line 5x+25y=11 is y = -5/11 x + 30/11
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