Respuesta :
The outlier of a dataset is a data element that is relatively far from the remaining data elements
- 99 is an outlier of pet group
- See attachment for the parallel box plots
(a) Prove that 99 is an outlier for Pet
We have:
Pets: 58 64 65 68 69 69 69 70 70 72 76 79 85 86 99
[tex]n = 15[/tex]
The quartiles positions are:
[tex]Q_1 = \frac{n + 1}{4}[/tex]
[tex]Q_1 = \frac{15 + 1}{4}[/tex]
[tex]Q_1 = \frac{16}{4}[/tex]
[tex]Q_1 = 4th[/tex]
[tex]Q_3 = Q_1 \times 3[/tex]
[tex]Q_3 = 4th \times 3[/tex]
[tex]Q_3 = 12th[/tex]
So, we have:
[tex]Q_1 = 4th[/tex]
[tex]Q_3 = 12th[/tex]
From the pet group:
The data elements at the 4th and 12th positions are 68 and 79
So, we have:
[tex]Q_1 = 68[/tex]
[tex]Q_3= 79[/tex]
The lower and upper limits of the outlier are:
[tex]L = Q_1 - 1.5 \times (Q_3 - Q_1)[/tex]
[tex]U = Q_3 + 1.5 \times (Q_3 - Q_1)[/tex]
So, we have:
[tex]L = 68 - 1.5 \times (79 - 68)[/tex]
[tex]L = 51.5[/tex]
[tex]U = 79+ 1.5 \times (79 - 68)[/tex]
[tex]U = 95.5[/tex]
This means that data below 51.5 or above 95.5 are outliers.
Hence, 99 is an outlier because 99 is greater than 95.5
(b) The parallel box plot
The three groups are:
Pets: 58 64 65 68 69 69 69 70 70 72 76 79 85 86 99
Erlento: 88 80 80 81 92 87 88 81 82 80 87 92 87 80 82
Alone: 62 70 73 75 77 80 84 84 84 87 87 87 90 91 99
See attachment for the parallel box plots
Read more about box plots and outliers at:
https://brainly.com/question/14940764
