Respuesta :
Answer:
Slope = -2/5 new points (5/2,1) and (5,0)
Step-by-step explanation:
Standard point slope equation:
y = mx + b where m is the slope and b is the y-intercept.
First find the slope between the given points.
Slope = rise/run
m = (y1 - y2) / (x1 - x2)
= (4 - 0)/(-5 - 5)
= 4/-10 = -2/5 then
y = (-2/5)x + b then one point (I picked (-5,4) to find b
4 = (-2/5)(-5) + b
4 = 2 + b
b = 2
y = (-2/5)x + 2 then pick an x and find y for additional points.
x = 5/2
y = (-2/5)(5/2) + 2
y = -1 + 2
y = 1 so the point is (5/2,1) and let x = 5
y = (-2/5)(5) + 2
y = -2 + 2
y = 0 so the point is (5,0)
Suppose that :
A = ( 5 , 0 )
B = ( - 5 , 4 )
Then we have :
Slope = [ y(B) - y(A) ] ÷ [ x(B) - x(A) ]
Slope = [ 4 - 0 ] ÷ [ -5 - 5 ]
Slope = 4 ÷ ( - 10 )
Slope = - 4/10
Slope = - 2/5
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It's time to find the formula of this linear function using following formula :
y - y ( A or B ) = Slope × ( x - x ( A or B ) )
I'm gonna using point A but u can do it with point B which will gave the same answer :
y - 0 = - 2/5 × ( x - 5 )
y = - 2/5 x + 2
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We have the formula of the function now thus it's time to find two more points that line passe through ;
To do that we just have to put two desired values of x instead of it and find the y to have the coordinate of those points that line passes through :
I'm gonna use x = - 10 and x = 15 :
x = - 10 x = 15
y = - 2/5 × ( -10 ) + 2 y = -2/5 × ( 15 ) + 2
y = 4 + 2 y = - 6 + 2
y = 6 y = - 4
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Thus ( -10 , 6 ) & ( 15 , - 4 ) are two other points that line passes through.