Answer:
#include <iostream>
using namespace std;
int main() {
int n = 0;
char c;
string str;
cin >> c >> str;
for (int i = 0; i < str.length(); ++i)
if (c == str[i]) n++;
cout << n << " n" << (n > 1 ? "'s" : "");
return 0;
}
Explanation:
Declares variables n, c, and str.
Next a loop lets count number of character c in string str.
Finally, answer is showing.
The complete code of the given program is provide below in the explanation segment.
Program explanation:
Program code:
#include <stdio.h>
#include <string.h>
int main()
{
char c;
char s[50];
int temp = 0, i;
//Read input
scanf(" %c", &c);
scanf("%s", s);
for (i = 0; i < strlen(s); ++i)
{
if (s[i] == c)
{
++temp;
}
}
if(temp!=1)
printf("%d %c's\n", temp,c);
else
printf("%d %c\n", temp,c);
return 0;
}
Output:
The attachment is provide below.
Learn more:
https://brainly.com/question/23254166
