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6. Two light bulbs are designed for use at 120 V and are rated at 75 W and 150 W. Which light bulb has the greater filament resistance? Why? ​

Respuesta :

[tex]\\ \bull\tt\longrightarrow P=\dfrac{V^2}{R}[/tex]

  • P is power
  • R is resistance

[tex]\\ \bull\tt\longrightarrow R=\dfrac{V^2}{P}[/tex]

Hence

[tex]\\ \bull\tt\longrightarrow R\propto V[/tex]

[tex]\\ \bull\tt\longrightarrow R\propto \dfrac{1}{P}[/tex]

  • Therefore if power is low then resistance will be high.

The first bulb has less power hence it has greater filament resistance.

samuelonum1

Comparing the results from the two data, we can see that the bulb with the Power rating of 75W has the greater resistance

Power and Energy

     Given Data

  • Power for Bulb one = 75W
  • Power for Bulb two = 150W
  • Voltage = 120V

The expression for Power in relation to Voltage and resistance is given as

P = V^2/R

R = V^2/P

Substitute the given data to solve for individual Resistance

R1 = 120^2/75

R1 = 14400/75

R1 = 192 ohms

R2 = 120^2/150

R2 = 14400/150

R2 = 96 ohms

Learn more Power here:

https://brainly.com/question/1199149

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