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12-09-2021
Mathematics

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Find the first three terms of the sequence below. Tn=n2+2n+9

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12-09-2021

[tex]\\ \bull\tt\longrightarrow T_n=n^2+2n+9[/tex]

[tex]\\ \bull\tt\longrightarrow T_1=1^2+2(1)+9=1+2+9=12[/tex]

[tex]\\ \bull\tt\longrightarrow T_2=2^2+2(2)+9=4+4+9=17[/tex]

[tex]\\ \bull\tt\longrightarrow T_3=3^2+2(3)+9=9+6+9=24[/tex]

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