Hi there!
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I believe your answer is:
[tex]y = \frac{2A-xz}{2x}; x \neq 0[/tex]
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Here’s why:
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[tex]2A = x(2y+z)\\\\\rightarrow x(2y+z)=2A\\\\\rightarrow\frac{x(2y+z)=2A}{x}\\\\\rightarrow 2y + z = \frac{2A}{x}\\\\\rightarrow 2y + z - z = \frac{2A}{x}-z\\\\\rightarrow 2y = \frac{2A}{x} - z\\\\\rightarrow\frac{2y = \frac{2A}{x} - z}{2}\\\\\rightarrow \boxed{y = \frac{2A-xz}{2x}}[/tex]
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Hope this helps you. I apologize if it’s incorrect.
