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Shania wanted her friend Radhika’s mobile number. But Radhika played a trick. She gave her a 10-digit mobile number she uses in India as 9 x y z p 7 q 1r 3 and told her to decode it with the help of following equations. Help her by solving equations. (Show your work)
(a) 2x-5 = 7
(b) 2(p + 1) = p + 4
(c) 5(y + 1) = 25
(d) 5(q –1) + 3q = 10 + 1
(e) 3−12+4= 1
(f) +14−8= 1
Given Mobile Number: 9 x y z p 7 q 1r 3

Respuesta :

This question involves basic arithmetic signs and simplifying of bracket terms.

Mobile number is; 9 6 4 1 2 7 8 1 2 3

a) 2x - 5 = 7

Add 5 to both sides to get;

2x = 12

x = 12/2

x = 6

b) 2(p + 1) = p + 4

Expanding the bracket gives;

2p + 2 = p + 4

Rearranging gives;

2p - p = 4 - 2

p = 2

c) 5(y + 1) = 25

Expanding the bracket gives;

5y + 5 = 25

5y = 25 - 5

5y = 20

y = 20/5

y = 4

d) 5(q –1) + 3q = 10 + 1

Expanding the bracket gives;

5q - 5 + 3q = 11

2q - 5 = 11

add 5 to both sides to get;

2q = 16

q = 16/2

q = 8

Question E and F are not clear but as it is r and z that are yet to be gotten, i have gotten the right equations from the brainly link at the end of this page.

e) 8z - 8 = 6z + 8

Rearranging, we have;

8z - 6z = 8 - 6

2z = 2

z = 2/2

z = 1

f) 3(r+10) + 200 = 236

Expanding the bracket and rearranging, we have;

3r + 30 = 236 - 200

3r = 236 - 200 - 30

3r = 6

r = 6/3

r = 2

So we now have;

x = 6; y = 4; z = 1; p = 2; q = 8; r = 2

Mobile number is; 9 6 4 1 2 7 8 1 2 3

Read more here; brainly.in/question/24417680?tbs_match=1

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