Respuesta :

naǫ
[tex]F(X)=6X-4 \hbox{ and } F(A)=26 \\ \hbox{substitute A for X:} \\ F(A)=6A-4 \\ 26=6A-4 \\ 26+4=6A \\ 30=6A \\ \frac{30}{6}=A \\ \boxed{A=5}[/tex]
26=6a -4
30 = 6am
(Divide both sides by 6)
A = 5

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