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10-10-2021
Chemistry

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How many ML of 0.44 M HCl are needed to dissolve 9.83 g of BaCO3

How many ML of 044 M HCl are needed to dissolve 983 g of BaCO3 class=

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yenxuan yenxuan

10-10-2021

Answer:

nBACO3=m/M=9,83/197=0,05(mol) ->nHCl=0,05.2/1=0,1(mol) =>VHCl=n/CM=0,1/0,44=0,227(lít)

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