Answer:
- Perimeter of the first triangle :
[tex] \longmapsto(x - 4) + (x - 5) + 5 \\ = x - 4 + x - 5 + 5 \\ = \boxed{2x - 4}[/tex]
- Perimeter of the second triangle :
[tex] \longmapsto(x - 10) + 10 + 16 \\ = x - 10 + 10 + 16 \\ = \boxed{x + 16}[/tex]
Now, it is given that the two triangles have same perimeter
So equating the value of the perimeter of the two triangles, we get
[tex] 2x - 4 = x + 16 \\2x - x = 16 + 4 \\ \boxed{ x = 20}[/tex]
Therefore, the value of x is 20
- x = 20 is the right answer.
