The De Broglie wavelength of the muon is calculated to be 4.13 × 10^10 m
We have the following information;
mass of the muon (m)= 206.8 × 9.11 × 10^-31 Kg = 1.88 × 10^-28 Kg
Plank's constant(h) = 6.6 × 10^-34 Js
Velocity of the muon(v) = 8.50×10^5 cm/s or 8500 m/s
From;
λ = h/mv
λ = 6.6 × 10^-34/1.88 × 10^-28 × 8500
λ = 6.6 × 10^-34/1.598 × 10^-24
λ = 4.13 × 10^10 m
Learn more: https://brainly.com/question/16103569