Hi there!
On an incline, the acceleration due to gravity is: (g = 9.81 m/s²)
a = gsinФ ≈ 1.196 m/s²
We can use the following kinematic equation to solve:
vf² = vi² + 2ad
Since the car will start to roll back when v = 0 m/s, we can write that vf = 0.
0 = vi² + 2ad
Plug in values:
0 = 31² + 2(-1.196)(d)
Rearrange for d:
31²/(2.392) = d
d = 401.756 m
