(02.06 MC) Figure ABCD is a rhombus, and m∠BAE = 9x + 2 and m∠BAD = 130°. Solve for x. Rhombus ABCD with diagonals AC and BD and point E as the point of intersection of the diagonals.

Respuesta :

An angle bisector divides an angle into equal parts.

The value of x is 7

The given parameters are:

[tex]\angle BAE = 9x + 2[/tex]

[tex]\angle BAD = 130^o[/tex]

Line AE is the angle bisector of [tex]\angle BAD[/tex]

This means that:

[tex]\angle BAD = 2 \times \angle BAE[/tex]

So, we have:

[tex]130 = 2 \times (9x + 2)[/tex]

Divide both sides by 2

[tex]65 = 9x + 2[/tex]

Subtract 2 from both sides

[tex]63 = 9x[/tex]

Divide both sides by 9

[tex]7 = x[/tex]

Rewrite as:

[tex]x = 7[/tex]

Hence, the value of x is 7

Read more about angle bisectors at:

https://brainly.com/question/12896755

Answer:

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Step-by-step explanation: