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Answer:
x² +2/3x -1/9 = 0
Step-by-step explanation:
The quadratic with roots p and q can be written as ...
(x -p)(x -q) = 0
x² -(p+q)x +pq = 0
For p=(-1-√2)/3 and q=(-1+√2)/3, we have ...
p +q = (-1-√2)/3 +(-1+√2)/3 = -2/3
pq = ((-1-√2)/3)((-1+√2)/3) = (1 -2)/9 = -1/9
Then the quadratic is ...
x² +2/3x -1/9 = 0
