Answer:
[tex]x=6\\y=12[/tex]
Step-by-step explanation:
To find the value of x you can use sin rule
[tex]sin(60)=\frac{oppoaite}{hypotenuse}\\\frac{\sqrt{3} }{2} =\frac{x}{4\sqrt{3} } \\[/tex]
Use cross multiplication
[tex]4*\sqrt{3} *\sqrt{3} =2x\\4*3=2x\\12=2x\\\frac{12}{2} =\frac{2x}{2} \\6 =x[/tex]
To find the value of y you have to use sin rule again
[tex]sin(30)=\frac{opposite}{hypotenuse}\\\frac{1}{2} =\frac{x}{y} \\\frac{1}{2} =\frac{6}{y} \\[/tex]
Use cross multiplication
[tex]y=6*2\\y=12[/tex]
Hope this helps you.
Let me know if you have any other questions :-)
