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A ball is thrown horizontally with an initial velocity of 5.0 meters per second.
The ball travels 15 meters horizontally before it lands. What vertical height
was it thrown from?

Respuesta :

leena

Hi there!

We can begin by calculating the total time of the ball's projectory:

t = d/v

t = 15/5 = 3 sec

We can use the simplified kinematic equation for time:

t = √2h/g

Rearrange to solve for h:

t² = 2h/g

gt² = 2h

gt²/2 = h

Plug in the values: (g = 9.8 m/s²)

9.8(3)² / 2 = 44.1 m

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