A large cargo ship dropped anchor in the ocean. The anchor was released at a constant rate rate of speed from a height of 44 meters

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Аноним Аноним · Answer 1 · 2021-10-11T20:15:43+02:00

Answer:

C and E

Step-by-step explanation:

The change in elevation was 44 + 20 = 64 m

the rate of fall was 64 m / 32 s = 2 m/s

The anchor reached the surface in 44 / 2 = 22 s so C is valid

E is correct as the ocean surface is origin and Up is the positive direction.

The anchor starts at 44 m above the surface and position is lower by 2 meters every second

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ogorwyne ogorwyne · Answer 2 · 2022-04-15T14:26:09+02:00

From the question, the two correct options about the speed with which the anchor was released are:

First we have to calculate the change that occurred in the elevation. Initially it was 44 meters but dropped 20 m below water.

44 + 20 = 64 meters

Next we calculate the rate with which the fall occurred

The time with which it fell was 32 seconds. = 64/32 = 2 meters pers second

44/2 = 22 hence it can be concluded that C is right.

Option E is also correct given that the water surface is above the ground and it is positive

Read more on distance here: https://brainly.com/question/2854969