Answer:
Step-by-step explanation:
You could graph it. I'll do that at the bottom. What you need is a value that is - on either 2 or 3 and a plus on the other one.
y=12*2^3 - 32x^2 + 17
y = 12 * 8 - 32*2^2 + 17
y = 96 - 128 + 17
y = -15
Now when x = 3 should give you something above the x axis
y = 12*3^3 - 32*9 + 17
y = 324 - 288 + 17
y = 53
What this indicates is that somewhere between 2 and 3 the graph crosses the x axis. The graph should indication that.
