If an object is placed 8 cm from a lens with a focal length of 4 cm, the image is 8 cm from the lens
Let the focal length be represented by f
Let the distance between the object and the lens be represented by u
Let the distance between the image and the lens be v
The focal length, f = 4 cm
The distance between the object and the lens, u = 8cm
The distance between the image and the lens, v = ?
The relationship between the focal length (f), distance between the object and the lens (u), and the distance between the image and the lens (v) is given below:
[tex]\frac{1}{u} + \frac{1}{v} = \frac{1}{f}[/tex]
Substitute f = 4, and u = 8 into the equation above:
[tex]\frac{1}{8} + \frac{1}{v} = \frac{1}{4} \\\\\frac{1}{v} = \frac{1}{4} - \frac{1}{8}\\\\\frac{1}{v} = \frac{2-1}{8}\\\\\frac{1}{v} = \frac{1}{8}\\\\v = 8[/tex]
Therefore, the image is 8 cm from the lens
Learn more here: https://brainly.com/question/19146043