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Quinn leaves her house at 10:00 am and runs 3 miles at a steady pace of 6 miles per
hour. She relaxes and takes a lunch break for 1 hour. She is pretty tired so she walks
home at a steady pace of 2 miles per hour. What time does Quinn return home

Respuesta :

Using the relation between velocity, distance and time, it is found that Quinn returns home at 1 pm.

Velocity is distance divided by time, that is:

[tex]v = \frac{d}{t}[/tex]

  • She walked 3 miles at a velocity of 6 miles per hour, thus [tex]d = 3, v = 6[/tex]. The time is:

[tex]v = \frac{d}{t}[/tex]

[tex]t = \frac{d}{v} = \frac{3}{6} = 0.5[/tex]

  • Thus, she arrived at 10:30 am, and took a lunch break of 1 hour, so she started to return at 11:30 am.
  • Distance of 3 miles, velocity of 2 miles per hour, thus [tex]d = 3, v = 2[/tex]. The time she took to return, in hours, is:

[tex]t = \frac{d}{v} = \frac{3}{2} = 1.5[/tex]

1.5 hours after 11:30 am is 1 pm, thus, Quinn returns home at 1 pm.

A similar problem is given at https://brainly.com/question/24316569

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