Respuesta :
Answer:
20 m by 10 m
Step-by-step explanation:
let w be width and l be length , then
2(l + w) = 60 ( divide both sides by 2 )
l + w = 30 ( subtract w from both sides )
l = 30 - w → (1)
lw = 200 → (2)
Substitute l = 30 - w into (2)
w(30 - w) = 200 ← distribute parenthesis on left side
30w - w² = 200 ( subtract 200 from both sides )
30w - w² - 200 = 0 ( multiply through by - 1 )
w² - 30w + 200 = 0 ← in standard form
(w - 10)(w - 20) = 0 ← in factored form
Equate each factor to zero and solve for w
w - 10 = 0 ⇒ w = 10
w - 20 = 0 ⇒ w = 20
Substitute these values into (1)
l = 30 - 10 = 20
l = 30 - 20 = 10
dimensions of field is 20 m by 10 m
Answer:
THIS IS THE REPRENTATION :I(LENGTH ),W(WIDTH)
2IW= 200
I,II USE THE SUBSTITUTION METHOD SINCE :I=30-W WE CAN SUBSTITUTE THE LENGTH TO 30
-W TO IW=200
(30-W)W=200
W2 + 30W=200---------------TRANSPOSE -w2
+30w
w2-30w +200 = 0------------------- USE FACTORING
(W-20)(w-10 =0----------------- THEN EQUATE EACH FACTOR TO ZERO
W- 20=0 W-10 =0
W=20 W=10
THEN SUBSTITUTE THE VALUE OF w TO ANY OF THE EQUATIONS TO GET THE VALUE OF I
Iw =200 Iw=200
I(20) =200 I(10)
I(20)/20= 200/20 I(10)/10
=200/10
I=10
