Respuesta :
- 2moles of H2O made when 6moles of HNO3 are consumed
Let required moles be x
[tex]\\ \sf\longmapsto \dfrac{2}{6}=\dfrac{x}{75}[/tex]
[tex]\\ \sf\longmapsto \dfrac{1}{3}=\dfrac{x}{75}[/tex]
[tex]\\ \sf\longmapsto x=\dfrac{75}{3}[/tex]
[tex]\\ \sf\longmapsto x=25mol[/tex]
2moles of H2O are made when 6moles of HNO3 are consumed
75 mole of HNO3 produces = [tex]\frac{2}{6}[/tex]× 75 ⇒ 25 moles of water
Limiting Reagent Method
The limiting reagent is the reactant that is completely used up in a reaction and thus determines when the reaction stops.
S + 6 HNO3 --> H2SO4 + 6 NO2 + 2 H2O
6 mole of HNO3 produces = 2 moles of H₂O
1 mole of HNO3 produces = [tex]\frac{2}{6}[/tex] mole of H₂O
∴ 75 mole of HNO3 produces = [tex]\frac{2}{6}[/tex]× 75 ⇒ 25 moles of water
Learn more about Limiting Reagent here :
https://brainly.com/question/23661051
#SPJ2
