If you change the 2 in front of 2O, to a 3, the result of the right side of the equation is [tex]3CO_2+6H_2O[/tex]
Given the chemical equation expressed as:
[tex]CH_4 + 2O_2 \rightarrow CO_2 + 2H_2O[/tex]
From the equation, we can see that 1 mole of methane reacts with 2 moles of oxygen to form 1 mole of carbon dioxide and 2 moles of water.
If the number of moles of oxygen is replaced with 3 moles, the correct equation will be expressed as:
[tex]3CH_4 + 2(3O_2) \rightarrow3CO2 + 6H2O[/tex]
This shows that if you change the 2 in front of 2O, to a 3, the result of the right side of the equation is [tex]3CO_2+6H_2O[/tex]
Learn more here: https://brainly.com/question/11904811
