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Let's take length of HK = n

By using trigonometry,

  • [tex] \sin(30) = \dfrac{22}{n} [/tex]

  • [tex] \dfrac{1}{2} = \dfrac{22}{n} [/tex]

  • [tex]n = 44[/tex]

Hence, value of HK = 44 cm

[tex]\\ \rm\Rrightarrow sin\theta=\dfrac{Perpendicular}{Hypotenuse}[/tex]

[tex]\\ \rm\Rrightarrow sin30=\dfrac{JK}{HK}[/tex]

[tex]\\ \rm\Rrightarrow sin30=\dfrac{22}{HK}[/tex]

[tex]\\ \rm\Rrightarrow HK=\dfrac{22}{sin30}[/tex]

[tex]\\ \rm\Rrightarrow HK=44[/tex]

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