A 0.56 kg block is suspended from the middle
of a 1.74 m long string. The ends of the string
are attached to the ceiling at points separated
by 1 m, and the block can slip along the long
string
The acceleration of gravity is 9.81 m/s?.
What angle does the string make with the
ceiling?

A 056 kg block is suspended from the middle of a 174 m long string The ends of the string are attached to the ceiling at points separated by 1 m and the block class=

Respuesta :

Notice that both strings have the same length, so they form an isosceles triangle, which means the angles they make with the ceiling are congruent.

If this angle has measure θ, then the angle between the two strings T₁ and T₂ has measure 180° - 2θ. This is because the interior angles of any triangle sum to 180°.

By the law of cosines, we have

(1 m)² = (0.87 m)² + (0.87 m)² - 2 (0.87 m)² cos(180° - 2θ)

Solve for θ :

(1 m)² = 2 (0.87 m)² - 2 (0.87 m)² cos(180° - 2θ)

(1 m)² / (2 (0.87 m)²) = 1 - cos(180° - 2θ)

cos(180° - 2θ) = 1 - (1 m)² / (2 (0.87 m)²)

cos(180° - 2θ) ≈ 0.3394

180° - 2θ = arccos(0.3394)

180° - 2θ ≈ 70.159°

2θ ≈ 109.841°

θ ≈ 54.9205° ≈ 55°

Ver imagen LammettHash