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A bank loaned out $25,000, part of it at the rate of 12% annual interest, and the rest at 4% annual interest. The total interest earned for both loans was $1,480.00. How much was loaned at each rate?

Respuesta :

Answer:

1875

Step-by-step explanation:

The bank loaned part of the $25,500 at a 6% interest rate. We will call this loan amount x. Then the rest of the 25,500 was loaned at a 9% interest rate. We will define this amount as 25,500 - x. We also know that the total interest earned was $1,875. With this information, we form the equation:

 

.06(x) + .09(25500 - x) = 1,875

.06x + (2,295 - .09x) = 1,875

Simplify the above equation to:

-.03x + 2,295 = 1,875

-.03x = -420

x = 14,000

Since x is the amount loaned at the 6% interest rate, we know that $11,500 was loaned at a 9% interest rate. (25,500 - 14,000 =11,500)

 

To figure out the amount loaned at 6%, subtract 11,500 from 25,500 ... this gives us 14,000. This means $14,000 was loaned at 6%.

To check:

14,000 x .06 = 840

11,500 x .09 = 1035

840 + 1035 = 1875